3(x^2)+5.5x-2.5=0

Solution for 3(x^2)+5.5x-2.5=0 equation:

3(x^2)+5.5x-2.5=0

a = 3; b = 5.5; c = -2.5;
Δ = b2-4ac
Δ = 5.52-4·3·(-2.5)
Δ = 60.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5.5)-\sqrt{60.25}}{2*3}=\frac{-5.5-\sqrt{60.25}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5.5)+\sqrt{60.25}}{2*3}=\frac{-5.5+\sqrt{60.25}}{6}
$